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Kw Ion Product for Water Tutorial

Key Concepts

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Kw Calculations at 25oC (298K)

Question 1: Calculate the hydroxide ion and hydrogen ion concentration of water at 25°C (~298K), Kw = 10-14.

Solution:

  1. Write the equation for the ion product for water:

    Kw = [H+][OH-]

  2. Substitute in the value for Kw:

    10-14 = [H+][OH-]

  3. Since [H+] = [OH-]

    10-14 = [H+]2

  4. Take the square root of both sides of the equation to find [H+]:

    √10-14 = √[H+]2
    √10-14 = [H+]
    [H+] = 10-7 mol L-1

  5. Since [H+] = [OH-],

    [OH-] = 10-7 mol L-1

Question 2: Calculate the pH and pOH of water at 25°C (298K).

Solution:

  1. Write the equation for calculating pH:

    pH = -log10[H+]

  2. Substitute in the value for [H+] calculated above:

    pH = -log10[10-7] = 7

  3. Write the equation for calculating pOH:

    pOH = -log10[OH-]

  4. Substitute in the value for [OH-] calculated above:

    pOH = -log10[10-7] = 7

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Temperature Dependence of Kw

The reaction

H2O(l) ⇋ H+(aq) + OH-(aq)

is endothermic, it absorbs heat.

H2O(l) ⇋ H+(aq) + OH-(aq)     ΔH is positive
or, writing the chemical equation with ΔH as a reactant:
H2O(l) + ΔH ⇋ H+(aq) + OH-(aq)

By Le Chatelier′s Principle if the temperature of the system is increased, the equilibrium position will shift to the right to minimise the effect of the increased temperature.

The forward reaction is favoured resulting in the production of more H+(aq) and more OH-(aq), so the value of Kw will increase (see K and Temperature).

Since the concentration of hydrogen ions is greater at higher temperatures, the pH of water will be lower at higher temperatures.

BUT, because the concentration of hydrogen ions in water is ALWAYS the same as the concentration of hydroxide ions in water, liquid water will ALWAYS be neutral!

The table below gives the value for the ion product for water, Kw, at various temperatures.
You should use these values to perform calculations to check the values given for [H+(aq)] and pH.

Temperature
(°C)
Kw [H+]
(mol L-1)
pH acidity
0 0.114 × 10-14 3.376 × 10-8 7.47 [H+] = [OH-] = neutral

10 0.293 × 10-14 5.413 × 10-8 7.27 [H+] = [OH-] = neutral

20 0.681 × 10-14 8.252 × 10-8 7.08 [H+] = [OH-] = neutral

25 1.008 × 10-14 1.004 × 10-7 7.00 [H+] = [OH-] = neutral

30 1.471 × 10-14 1.213 × 10-7 6.92 [H+] = [OH-] = neutral

40 2.916 × 10-14 1.708 × 10-7 6.77 [H+] = [OH-] = neutral

50 5.476 × 10-14 2.340 × 10-7 6.63 [H+] = [OH-] = neutral

100 51.3 × 10-14 7.162 × 10-7 6.14 [H+] = [OH-] = neutral

Note that :

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