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Types of Structural Isomers Organic Chemistry Tutorial

Key Concepts

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Chain Isomers (Skeletal Isomers)

Consider an alkane molecule with the molecular formula C4H10.
We know that each carbon atom will be covalently bonded to 4 other atoms and that each hydrogen atom will be covalently bonded to just 1 other atom.
So we could draw a possible structure for the molecule as shown below:

  H
|
  H
|
  H
|
  H
|
 
H− C C C C −H
  |
H
  |
H
  |
H
  |
H
 
butane, C4H10

This molecule is called butane and it is referred to as a straight chain alkane because all the carbon atoms have bonded in a single line called the carbon skeleton.

There is another molecule with the molecular formula C4H10 that we could draw:

      H
|
     
  H
|
H
 
-C-
|
H
 
H
|
 
H− C C C −H
  |
H
  |
H
  |
H
 
2-methylpropane, C4H10

This molecule, 2-methylpropane, is also an alkane but only 3 of the carbon atoms are joined in a chain, while a fourth carbon atom has branched-off the long chain, indeed we call this CH3 group a branch, or a side-chain, and the molecule 2-methylpropane is referred to as a branched chain alkane.

Butane and 2-methylpropane are said to be structural isomers because they have same the molecular formula but a different arrangement of the atoms making up the structural formula. But because the only difference in the structural formula of butane and 2-methylpropane is that butane is a straight chain molecule and 2-methylpropane contains a branch, or side-chain, we refer to these 2 molecules as chain isomers, or skeletal isomers.
They are called chain isomers because they have different numbers of carbon atoms in the longest carbon chain.
Since this longest carbon chain is also known as the molecule's skeleton, these the isomers are also known as skeletal isomers.

Chain Isomers of C4H10
(Skeletal Isomers of C4H10)
butane 2-methylpropane
  H
|
  H
|
  H
|
  H
|
 
H− C C C C −H
  |
H
  |
H
  |
H
  |
H
 
straight chain alkane
      H
|
     
  H
|
H
 
-C-
|
H
 
H
|
 
H− C C C −H
  |
H
  |
H
  |
H
 
branched chain alkane

You can produce chain isomers (skeletal isomers) for other classes of molecules besides hydrocarbons.
For example, if we substitute an hydroxyl (OH) functional group for a hydrogen atom on the first carbon atom of butane we would have the alkanol known as butan-1-ol (C4H10O):

  H
|
  H
|
  H
|
  H
|
 
HO C C C C −H
  |
H
  |
H
  |
H
  |
H
 
butan-1-ol, C4H10O

Butan-1-ol (1-butanol) is a straight chain alkanol, all 4 carbon atoms are linked to form a single chain. There are no branches (no side-chains).

But we could also draw a different structural formula for an alkan-1-ol with the same molecular formula, C4H10O, as shown below:

      H
|
     
  H
|
H
 
-C-
|
H
 
H
|
 
HO C C C −H
  |
H
  |
H
  |
H
 
2-methylpropan-1-ol, C4H10O

Note that both butan-1-ol and 2-methylpropan-1-ol have the same molecular formula, C4H10O, and the OH functional group is located on the same carbon atom (the first carbon atom) in both molecules, BUT, butane is a straight chain alkan-1-ol while 2-methylpropan-1-ol is a branched chain alkan-1-ol, so butan-1-ol and 2-methylpropan-1-ol are chain isomers (or skeletal isomers).

Chain Isomers of C4H10O
(Skeletal Isomers of C4H10O)
butan-1-ol 2-methylpropan-1-ol
  H
|
  H
|
  H
|
  H
|
 
HO C C C C −H
  |
H
  |
H
  |
H
  |
H
 
straight chain alkan-1-ol
      H
|
     
  H
|
H
 
-C-
|
H
 
H
|
 
HO C C C −H
  |
H
  |
H
  |
H
 
branched chain alkan-1-ol

2 molecles are chain isomers if they have:

  1. same molecular formula
  2. same functional group (if any) located in the same position
  3. different numbers of carbon atoms in each branch or side-chain (0, 1, 2, etc)

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Position Isomers (Regioisomers)

Let's keep thinking about alkanols with the molecular formula C4H10O.
In the section above we draw a structural formula for butan-1-ol, a straight chain alkanol in which the OH functional group is located on the first carbon atom of the chain.
In the diagram below, we have numbered the carbon atoms 1, 2, 3 and 4:

butan-1-ol, C4H10O
  H
|
  H
|
  H
|
  H
|
 
HO C1 C2 C3 C4 −H
  |
H
  |
H
  |
H
  |
H
 

If the OH functional group was positioned on carbon 2 instead of carbon 1, we would have a different structural isomer because, although the molecular formula remains the same, the structural formula will be different:

butan-2-ol, C4H10O
  H
|
  HO
 |
  H
|
  H
|
 
H− C1 C2 C3 C4 −H
  |
H
  |
H
  |
H
  |
H
 

In terms of their structural formula, the only difference between these two molecules (butan-1-ol and butan-2-ol) is the position of the OH functional group along the chain of 4 carbon atoms, so these 2 molecules are referred to as position isomers.

Position Isomers for Straight Chain Alkanols of C4H10O
butan-1-ol butan-2-ol
  H
|
  H
|
  H
|
  H
|
 
HO C1 C2 C3 C4 −H
  |
H
  |
H
  |
H
  |
H
 
  H
|
  HO
 |
  H
|
  H
|
 
H− C1 C2 C3 C4 −H
  |
H
  |
H
  |
H
  |
H
 

Similarly we could draw 2 different position isomers for the branched chain alkanols with molecular formula C4H10O (2-methylpropan-1-ol and 2-methylpropan-2-ol) as shown below:

Position Isomers for Branched Chain Alkanols of C4H10O
2-methylpropan-1-ol 2-methylpropan-2-ol
      H
|
     
  H
|
H
 
-C-
|
H
 
H
|
 
HO C1 C2 C3 −H
  |
H
  |
H
  |
H
 
branched chain alkan-1-ol
      H
|
     
  H
|
H
 
-C-
|
H
 
H
|
 
H− C1 C2 C3 −H
  |
H
   |
HO
  |
H
 
branched chain alkan-2-ol

Molecules are referred to as position isomers if they have:

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Functional Group Isomers (Functional Isomers)

Let's continue thinking about molecules with the molecular formula C4H10O.
So far we have drawn 4 molecules with the same molecular formula but different structural formula.
All 4 molecules have belonged to a class of compounds known as alcohols, molecules in which an OH functional group has substituted for an H atom in the saturated parent alkane.
But does the functional group have to be OH?
Couldn't we position an oxygen atom (O) between 2 carbon molecules?
Yes we could and this would produce a molecule belonging to a different class of compounds called ethers

  H
|
  H
|
  H
|
  H
|
 
H− C C -O- C C −H
  |
H
  |
H
  |
H
  |
H
 
1-ethoxyethane
(diethyl ether)
(ethyl ether)

For example, butan-1-ol and 1-ethoxyethane are functional group isomers because they have the same molecular formula (C4H10O) but different functional groups (hydroxyl, OH, functional group in butan-1-ol and the ether, -O-, functional group in 1-ethyoxyethane):

Functional Group Isomers of C4H10O
butan-1-ol 1-ethoxyethane
  H
|
  H
|
  H
|
  H
|
 
HO C C C C −H
  |
H
  |
H
  |
H
  |
H
 
  H
|
  H
|
  H
|
  H
|
 
H− C C -O- C C −H
  |
H
  |
H
  |
H
  |
H
 
-OH functional group -O- functional group

Functional group isomers have:

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Worked Example of Types of Structural Isomers

Problem: Draw structural isomers of C2H6O and classify them as either chain isomers, position isomers, or, functional group isomers.

Solution to the problem:

(Based on the StoPGoPS approach to problem solving in chemistry)

  1. What is the question asking you to do?

    Draw and classify structural isomers of C2H6O

  2. What data (information) have you been given in the question?

    Extract the data from the question:

    molecular formula: C2H6O

  3. What is the relationship between what you know and what you need to find out?

    (1) Structural isomers have the same molecular formula but different structural formulae (arrangement of atoms)

    (2) Chain isomers: different branching, same functional group in same location

    (3) Position isomers: different position of same functional group, same branching

    (4) Functional group isomers: different functional groups

  4. Draw isomers of C2H6O

    Only 2 carbon atoms so only straight chain isomers are possible:

      H
    |
      H
    |
     
    HO− C(1) C(2) −H
      |
    H
      |
    H
     
    ethan-1-ol
      H
    |
      H
    |
     
    H− C(1) C(2) −OH
      |
    H
      |
    H
     
    ethan-2-ol

    But these are not structural isomers!
    If you rotate ethan-2-ol 180° in space you would have the same structural formula as ethan-1-ol.
    Put another way, if you number the carbon atoms in "ethan-2-ol" from right to left (instead of left to right as shown), then the OH functional group is attached to carbon (1) and the name of the molecule is ethan-1-ol.
    There is only one way to draw a structural formula for an alkanol with the molecular formula C2H6O, and the molecule is called ethanol.

    But we can draw a structural formula in which the O atom covalently bonds to 2 carbon atoms:

      H
    |
      H
    |
     
    H− C −O− C −H
      |
    H
      |
    H
     
    methoxymethane
    (methyl ether)
    (dimethyl ether)

    Ethanol and methoxymethane are structural isomers because they have the same molecular formula (C2H6O) but different structural formula.

  5. Classify the two isomers of C2H6O

    Ethanol contains the hydroxyl (-OH) functional group.

    Methoxymethane contains the ether (-O-) functional group.

    Since ethanol and methoxymethane are structual isomers that have different functional groups, they are classed as functional group isomers (or functional isomers).

  6. Is your answer plausible?

    Have we answered the question?

    Yes, because we have :

    ⚛ drawn two structural isomers of C2H6O

    ⚛ classified them as functional group isomers

    Check that these 2 isomers are in fact functional group isomers:

    Isomer 1
    (ethanol)
    Isomer 2
    (methoxymethane)
      H
    |
      H
    |
     
    HO− C C −H
      |
    H
      |
    H
     
      H
    |
      H
    |
     
    H− C −O− C −H
      |
    H
      |
    H
     

    Are the two molecules structural isomers?

    Yes, they have:

    ⚛ same molecular formula C2H6O

    ⚛ different arrangement of atoms in the structural formula

    Are the two molecules functional group isomers?

    Yes, they are structural isomers with different functional groups:

    ⚛ Isomer 1 (ethanol) has an -OH functional group

    ⚛ Isomer 2 (methoxymethane) has an -O- functional group

  7. State your solution to the problem "draw and classify structural isomers of C2H6O":

    Functional Group Isomers of C2H6O
      H
    |
      H
    |
     
    HO− C C −H
      |
    H
      |
    H
     
      H
    |
      H
    |
     
    H− C −O− C −H
      |
    H
      |
    H