go to the AUS-e-TUTE homepage

IUPAC Naming of Salts (Binary Inorganic Ionic Compounds) Introductory Chemistry Tutorial

Key Concepts

Please do not block ads on this website.
No ads = no money for us = no free stuff for you!

Naming Salts Given the Formula for the Salt

Recall that in the formula of a salt (MaXb):

The formula of the salt (MaXb) tells is it is made up of two ions:

The formula of the salt (MaXb) tells us the number of ions present:

Recall that if there is only 1 cation present the formula would be MXb
If only 1 anion is present the formula would be MaX
If there is only 1 cation and 1 anion present the formula would be MX

If more than one polyatomic cation is present in the salt formula, then the formula of the polyatomic cation is enclosed in parentheses (M):
(M)(a)Xb

If more than one polyatomic anion is present in the salt formula, then the formula of the polyatomic anion is enclosed in parentheses (X):
M(a)(X)b

If the formula of the salt is composed of more than one cation and more than one anion, then the formula would be (M)a(X)b

A salt has no overall charge, this means that the total positive charge of all the cations present in the salt's formula is exactly balanced by the total negative charge due to all the anions present in the formula of the salt.

We can use this information in the formula of a salt (MaXb) to help us name that salt, as shown in the steps below:

  1. Break the formula of the salt up into two parts:

    (i) cation (first part of the formula)

    (ii) anion (last part of the formula)

    Salt MaXb
    cation anion
    M X

  2. Name the anion present in salt MaXb using one of these methods:

    (i) name of anion of non-metal element

    (ii) recall of formula and name of polyatomic anions

    Salt MaXb
    cation anion
    M Xy-
      anion name

  3. Determine the individual charge on each anion (Xy-) in salt MaXb using either of these methods:

    (i) location in periodic table for monoatomic non-metal anions

    (ii) recall of formula and name of polyatomic anions

    charge on one anion = y-

  4. Determine the total charge on all anions in salt MaXb by multiplying the charge on each anion by the number of anions present:

    total charge due to all anions = b × y-

  5. Determine the total charge on all cations in salt MaXb which will be the same as the total charge of all anions, BUT, with the opposite sign:

    total charge due to all cations = -(b × y-)

  6. Determine the individual charge on each cation in salt MaXb by dividing the total charge due to all cations by the number of cations (a)

    charge on one cation = total charge due to all cations ÷ a

  7. Name the cation based on either of these methods:

    (i) monoatomic metal cations: name(charge in parentheses)

    (ii) polyatomic cation: name only required

    Note that the names of Group 1 and Group 2 metals do not require the charge number to be placed in parentheses after then name of the cation

  8. Assemble the name of the salt remember to leave a space between the name of the cation and the name of the anion

    Salt MaXb
    cation anion
    Mx+ Xy-
    cation name anion name

Do you know this?

Join AUS-e-TUTE!

Play the game now!

Worked Example: Naming Salts Composed of Monoatomic Ions

Question 1: Name the salt that has the formula NaI

Solution:

  1. Break the formula of the salt up into two parts:

    (i) cation (first part of formula)

    (ii) anion (last part of formula)

    Salt NaI
    cation anion
    Na I

  2. Name the anion present in salt NaI using one of these methods:

    (i) name of anion of non-metal element : I is the symbol for iodine therefore anion is named iodide

    (ii) recall of formula and name of polyatomic anions

    Salt NaI
    cation anion
    Na I-
      iodide

  3. Determine the individual charge on each anion in salt NaI using either of these methods:

    (i) location in periodic table for monoatomic non-metal anions : iodine is group 17 element so its charge number is 1-

    (ii) recall of formula and name of polyatomic anions

    charge on one anion = 1-

  4. Determine the total charge on all anions in salt NaI by multiplying the charge on each anion by the number of anions present:

    total charge due to all anions = 1 × 1- = 1-

  5. Determine the total charge on all cations in salt NaI which will be the same as the total charge of all anions, BUT, with the opposite sign:

    total charge due to all cations = -(1-) = 1+

  6. Determine the individual charge on each cation in salt NaI by dividing the total charge due to all cations by the number of cations

    charge on one cation = 1+ ÷ 1 = 1+

  7. Name the cation based on either of these methods:

    (i) monoatomic metal cations: Na is the chemical symbol for sodium, cation is therefore sodium(1+)

    (ii) polyatomic cation: name only required

    Note that the names of Group 1 and Group 2 elements do not require the charge number to be placed in parentheses after the name of the cation

    cation name is therefore sodium

  8. Assemble the name of the salt remembering to leave a space between the name of the cation and the name of the anion

    Salt NaI
    cation anion
    Na+ I-
    sodium iodide

    NaI has the name sodium iodide

Question 2: Name the salt that has the formula FeCl2

Solution:

  1. Break the formula of the salt up into two parts:

    (i) cation (first part of formula)

    (ii) anion (last part of formula)

    Salt FeCl2
    cation anion
    Fe Cl

  2. Name the anion present in salt FeCl2 using one of these methods:

    (i) name of anion of non-metal element : Cl is the symbol for chlorine therefore anion is named chloride

    (ii) recall of formula and name of polyatomic anions

    Salt FeCl2
    cation anion
    Fe Cl-
      chloride

  3. Determine the individual charge on each anion in salt FeCl2 using either of these methods:

    (i) location in periodic table for monoatomic non-metal anions : chlorine is group 17 element so its charge number is 1-

    (ii) recall of formula and name of polyatomic anions

    charge on one anion = 1-

  4. Determine the total charge on all anions in salt FeCl2 by multiplying the charge on each anion by the number of anions present:

    total charge due to all anions = 2 × 1- = 2-

  5. Determine the total charge on all cations in salt FeCl2 which will be the same as the total charge of all anions, BUT, with the opposite sign:

    total charge due to all cations = -(2-) = 2+

  6. Determine the individual charge on each cation in salt FeCl2 by dividing the total charge due to all cations by the number of cations

    charge on one cation = 2+ ÷ 1 = 2+

  7. Name the cation based on either of these methods:

    (i) monoatomic metal cations: Fe is the chemical symbol for iron, cation is therefore iron(2+)

    (ii) polyatomic cation: name only required

    Note iron can exist as cations with different charge numbers so it requires the charge number to be placed in parentheses after the name of the cation

    Recommended cation name is therefore iron(2+)
    (iron(II) is not a recommended name, neither is ferrous a recommended name)

  8. Assemble the name of the salt remembering to leave a space between the name of the cation and the name of the anion

    Salt FeCl2
    cation anion
    Fe2+ Cl-
    iron(2+) chloride

    The recommended name for FeCl2 is iron(2+) chloride
    (iron(II) chloride is not a recommended name)
    (ferrous chloride is not a recommended name)

Do you understand this?

Join AUS-e-TUTE!

Take the test now!

Worked Example: Naming Salts Composed of Polyatomic Ions

Question 1: Name the salt that has the formula CuSO4

Solution:

  1. Break the formula of the salt up into two parts:

    (i) cation (first part of formula)

    (ii) anion (last part of formula)

    Salt CuSO4
    cation anion
    Cu SO4

  2. Name the anion present in salt CuSO4 using one of these methods:

    (i) name of anion of non-metal element

    (ii) recall of formula and name of polyatomic anions: SO42- has the name sulfate

    Salt CuSO4
    cation anion
    Cu SO42-
      sulfate

  3. Determine the individual charge on each anion in salt CuSO4 using either of these methods:

    (i) location in periodic table for monoatomic non-metal anions

    (ii) recall of formula and name of polyatomic anions: charge on sulfate is 2-

    charge on one anion = 2-

  4. Determine the total charge on all anions in salt CuSO4 by multiplying the charge on each anion by the number of anions present:

    total charge due to all anions = 1 × 2- = 2-

  5. Determine the total charge on all cations in salt CuSO4 which will be the same as the total charge of all anions, BUT, with the opposite sign:

    total charge due to all cations = -(2-) = 2+

  6. Determine the individual charge on each cation in salt CuSO4 by dividing the total charge due to all cations by the number of cations

    charge on one cation = 2+ ÷ 1 = 2+

  7. Name the cation based on either of these methods:

    (i) monoatomic metal cations: Cu is the chemical symbol for copper, cation is therefore copper(2+)

    (ii) polyatomic cation: name only required

    Note that the names of Group 1 and Group 2 elements do not require the charge number to be placed in parentheses after the name of the cation

    name of cation is therefore copper(2+)

  8. Assemble the name of the salt remembering to leave a space between the name of the cation and the name of the anion

    Salt CuSO4
    cation anion
    Cu2+ SO42-
    copper(2+) sulfate

    CuSO4 has the name copper(2+) sulfate
    (copper(II) sulfate is not a recommended name)
    (cupric sulfate is not a recommended name)
    (Note: when people refer to "copper sulfate", they mean copper(2+) sulfate)

Question 2: Name the salt that has the formula Ca(OH)2

Solution:

  1. Break the formula of the salt up into two parts:

    (i) cation (first part of formula)

    (ii) anion (last part of formula)

    Salt Ca(OH)2
    cation anion
    Ca OH

  2. Name the anion present in salt Ca(OH)2 using one of these methods:

    (i) name of anion of non-metal element

    (ii) recall of formula and name of polyatomic anions: OH- has the name hydroxide

    Salt Ca(OH)2
    cation anion
    Ca OH-
      hydroxide

  3. Determine the individual charge on each anion in salt Ca(OH)2 using either of these methods:

    (i) location in periodic table for monoatomic non-metal anions

    (ii) recall of formula and name of polyatomic anions: charge on hydroxide is 1-

    charge on one anion = 1-

  4. Determine the total charge on all anions in salt Ca(OH)2 by multiplying the charge on each anion by the number of anions present:

    total charge due to all anions = 2 × 1- = 2-

  5. Determine the total charge on all cations in salt Ca(OH)2 which will be the same as the total charge of all anions, BUT, with the opposite sign:

    total charge due to all cations = -(2-) = 2+

  6. Determine the individual charge on each cation in salt Ca(OH)2 by dividing the total charge due to all cations by the number of cations

    charge on one cation = 2+ ÷ 1 = 2+

  7. Name the cation based on either of these methods:

    (i) monoatomic metal cations: Ca is the chemical symbol for calcium, cation is therefore calcium(2+)

    (ii) polyatomic cation: name only required

    Note that the names of Group 1 and Group 2 elements do not require the charge number to be placed in parentheses after the name of the cation

    name of cation is therefore calcium

  8. Assemble the name of the salt remembering to leave a space between the name of the cation and the name of the anion

    Salt Ca(OH)2
    cation anion
    Ca2+ OH-
    calcium hydroxide

    Ca(OH)2 has the name calcium hydroxide

Question 3: Name the salt that has the formula (NH4)2SO4

Solution:

  1. Break the formula of the salt up into two parts:

    (i) cation (first part of formula)

    (ii) anion (last part of formula)

    Salt (NH4)2SO4
    cation anion
    NH4 SO4

  2. Name the anion present in salt (NH4)2SO4 using one of these methods:

    (i) name of anion of non-metal element

    (ii) recall of formula and name of polyatomic anions: SO42- has the name sulfate

    Salt Ca(OH)2
    cation anion
    NH4 SO42-
      sulfate

  3. Determine the individual charge on each anion in salt (NH4)2SO4 using either of these methods:

    (i) location in periodic table for monoatomic non-metal anions

    (ii) recall of formula and name of polyatomic anions: charge on sulfate is 2-

    charge on one anion = 2-

  4. Determine the total charge on all anions in salt (NH4)2SO4 by multiplying the charge on each anion by the number of anions present:

    total charge due to all anions = 1 × 2- = 2-

  5. Determine the total charge on all cations in salt (NH4)2SO4 which will be the same as the total charge of all anions, BUT, with the opposite sign:

    total charge due to all cations = -(2-) = 2+

  6. Determine the individual charge on each cation in salt (NH4)2SO4 by dividing the total charge due to all cations by the number of cations

    charge on one cation = 2+ ÷ 2 = 1+

  7. Name the cation based on either of these methods:

    (i) monoatomic metal cations

    (ii) polyatomic cation: NH4+ is most often referred to as ammonium

    Note that the names of Group 1 and Group 2 elements do not require the charge number to be placed in parentheses after the name of the cation

    name of cation is therefore ammonium

  8. Assemble the name of the salt remembering to leave a space between the name of the cation and the name of the anion

    Salt (NH4)2SO4
    cation anion
    NH4+ SO42-
    ammonium sulfate

    (NH4)2SO4 has the name ammonium sulfate

Can you apply this?

Join AUS-e-TUTE!

Take the exam now!


Footnotes: reference "Nomenclature of Inorganic Chemistry: IUPAC Recommendations 2005" (Red Book)

(1) monoatomic or monotomic or monatomic? The IUPAC document cited above uses monoatomic so we will too!

(2) There are 3 primary IUPAC systems for naming an inorganic compound:
Compositional (stoichiometric) nomenclature : requires no understanding of the structure of the connections within the compound and is the system of nomenclature we will use here in this introduction to IUPAC naming of inorganic salts.
Substitutive nomenclature : requires an understanding of connections within the structure of the compound
Additive nomenclature : requires an understanding of connections within the structure of the compound and this is the most generally applicable system for inorganic compounds

(3) Oxidation state as roman numerals placed in parentheses after name of element is no longer recommended as a naming convention by IUPAC.

(4) Originally the latin form of these elements' names were used with the "ous" ending for the lower oxidation state and the "ic" ending for the higher oxidation state.

(5) The name of the element with the symbol Cs is caesium, but IUPAC also accepts the alternative spelling of cesium.

(6) We are only discussing the monoatomic anions here, O2-, not polyatomic anions like the dioxide anion and trioxide anions (similarly for other non-metals that form polyatomic ions like sulfur and iodine for example)
Compositional names are not recommended for use with polyatomic ions of elements.
The compositional and additive names of Group 1 oxides follow the example of potassium as shown below:
K2O dipotassium oxide (potassium oxide)
K2O2 potassium dioxide(2-) and additive name: dipotassium (dioxide)
KO2 potassium dioxide(1-) and additive name monopotassium (dioxide)
KO3 potassium trioxide(1-) and additive name potassium (trioxide)

(7) To be consistent with the rules for the construction of a formula (order of increasing electronegativity, that is symbol for least electronegative atom written first, symbol for most electronegative element written last), hydroxide should be given the formula HO- NOT OH-. However, the formula OH- for hydroxide is well established and accepted.
Systematic IUPAC names for hydroxide are:

  • oxidanide (substitutive name : water, H2O, named as oxidane, negative ion produced by dehydronation (deprotonation) is HO- hence named as oxidanide)
  • hydridooxygenate(1-) (additive name)