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Periodic Table: Trends in Group 17 Elements (halogens) Chemistry Tutorial

Key Concepts

Summary of trends in the properties of Group 17 elements is shown below:

Increasing Trend: Name Decreasing Trend:
Atomic Radius Melting Point Metallic Character Reactivity Electronegativity First Ionisation Energy
smallest lowest least metallic fluorine most reactive largest highest
chlorine
bromine
largest highest most metallic iodine least reactive smallest lowest

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Data Table for Group 17 Elements (Halogens)

Inspect the data in the table below for Group 17 elements.

Can you identify any patterns, or trends, in the data?

Period Name
(Symbol)
Atomic Number (Z) Simple Electronic Configuration Atomic Radius
(pm)
Electro-
negativity
(Pauling)
1stIonization Energy (IA(kJ mol-1) Melting point (°C) Boiling point (°C) Physical Appearanceat STP (0°C, 100 kPa) Colour of Gas
2 Fluorine
(F)
9 2,7 68 3.98 1690 -223 -187 pale yellow gas pale yellow

3 Chlorine
(Cl)
17 2,8,7 99 3.16 1260 -102 -35 greenish-yellow gas greenish-yellow

4 Bromine
(Br)
35 2,8,18,7 114 2.96 1150 -7.3 59 reddish-brown liquid orange

5 Iodine
(I)
53 2,8,18,18,7 133 2.66 1020 114 183 dark grey solid violet

6 Astatine (3)
(At)
85 2,8,18,32,18,7   2.2 899  

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Trends in the Physical Properties of Group 17 Elements

Consider the melting points and boiling points of the Group 17 elements as shown in the table below:

Name Formula Melting Point (°C) Boiling Point (°C) Trend
fluorine F2 -223 -187 lowest
chlorine Cl2 -102 -35
bromine Br2 -7.3 59
iodine I2 114 183 highest

As you go down group 17 from top to bottom, the melting point of the elements increases and the boiling point increases.

We can use the melting point and boiling point to determine the state of each element at standard temperature and pressure (25°C, 100 kPa).

If element is a:

So let's take another look at the melting points (M.P.) and boiling points (B.P.) of the group 17 elements and decide which are gases, liquids and solids:

Name Formula Melting Point
(M.P. °C)
Boiling Point
(B.P. °C)
State
fluorine F2 -223 -187 B.P. < 25°C gas
chlorine Cl2 -102 -35 B.P. < 25°C gas
bromine Br2 -7.3 59 M.P. < 25°C < B.P. liquid
iodine I2 114 183 25°C < M.P. solid

We can see a trend in the states of matter. Going down Group 17 from top to bottom the elements change from gaseous state to liquid to solid.

The melting point of a substance reflects the amount of energy required to weaken the forces of attraction between molecules (intermolecular forces), the higher the melting point the stronger the forces of attraction between the molecules.
We can infer that there is a gradation in the intermolecular forces acting between the molecules such that the strongest forces of attraction act between iodine molecules and the weakest forces of attraction act between fluorine molecules.

There is also a gradation in the colour of the elements going down group 17 from top to bottom:
pale yellow to greenish-yellow to reddish-brown to gray

This is why we say that the properties of group 17 elements become more metallic in character as you go down the group from top to bottom, even though all the elements in group 17 are non-metals.

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Trends in the Chemical Properties of Group 17 Elements

As you go down group 17 from top to bottom the number of occupied electron shells (or energy levels) increases as shown in the table below:

Name Electronic Configuration No. Occupied Energy Levels (shells) Trend
fluorine 2,7 2 lowest
chlorine 2,8,7 3
bromine 2,8,18,7 4
iodine 2,8,18,18,7 5 highest

As each successive atom gains an additional electron shell (energy level), the radius of the atom increases as shown in the table below:

Name Electronic Configuration Atomic Radius (pm) Trend
fluorine 2,7 68 lowest
chlorine 2,8,7 99
bromine 2,8,18,7 114
iodine 2,8,18,18,7 133 highest

The negatively charged valence electrons are getting further away from the positively charged nucleus so they feel less of a "pull" towards the nucleus.
Successive filled electron shells (energy levels) are said to "shield" the valence electrons.
This means that you as go down the group from top to bottom an electron is easier to remove from the atom because it is less strongly attracted towards the nucleus.
The energy required to remove an electron from a gaseous atom is known as its "first ionisation energy".
We can see the trend in first ionisation energy of the group 17 elements decreases as we go down the group from top to bottom as shown in the table below:

1st Ionisation Reaction 1st Ionisation Energy (kJ mol-1) Trend
F(g) → F-(g) + e- 1690 highest
Cl(g) → Cl-(g) + e- 1260
Br(g) → Br-(g) + e- 1150
I(g) → I-(g) + e- 1020 lowest

While it is easier to pull an electron off an iodine atom compared to pulling an electron off an atom of fluorine, these numbers are all quite high.
It requires quite a lot of energy to remove an electron from any of these atoms.
Losing an electron is not the preferred method by which a halogen would form a compound.

If we take a look at the electronic configuration of the group 17 element atoms, we can see something that doesn't change down the group:

Name Electronic Configuration of Atom
fluorine 2,7
chlorine 2,8,7
bromine 2,8,18,7
iodine 2,8,18,18,7

The atoms of group 17 elements all have 7 electrons in the valence shell (highest energy level).

So, what if a halogen atom gained an electron instead of losing an electron, as shown in the equations below:

F + e- → F-

Cl + e- → Cl-

Br + e- → Br-

I + e- → I-

What would the electronic configuration of these "halide" ions look like?
We've done this in the table below:

Name Atom's Electronic Configuration   Anion's Electronic Configuration
fluorine 2,7 + e- 2,8
chlorine 2,8,7 + e- 2,8,8
bromine 2,8,18,7 + e- 2,8,18,8
iodine 2,8,18,18,7 + e- 2,8,18,18,8

And this is what people mean when they refer to an "atom" completing its "octet" of electrons ("oct" means 8).
This is a stable electronic configuration.
In fact, each of these electronic configurations is now the same as a Noble Gas (very unreactive group 18 element).
We say that each halide ion is isoelectronic with its neighboring Noble Gas (Group 18) element as shown in the table below:

Formula of Anion
(halide ion)
Anion's Electronic Configuration Isoelectronic with:
F- 2,8 Ne
Cl- 2,8,8 Ar
Br- 2,8,18,8 Kr
I- 2,8,18,18,8 Xe

There is supporting evidence for this desire of a halogen atom to pull an electron towards itself from the values for electronegativity:

Name Electronegativity
(Pauling)
Trend
fluorine 3.98 most electronegative
chlorine 3.16
bromine 2.96
iodine 2.66 least electronegative

Firstly, all the halogen atoms are very electronegative, they are all very capable of pulling an electron towards themselves.
Remember, gaining an electron is favourable for halogens because it enables them to form an anion with the same electron configuration as a stable Group 18 (Noble Gas) element.

Secondly, this ability to attract electrons towards the nucleus of the atom decreases as you go down group 17 from top to bottom, fluorine is more electronegative than chlorine which is more electronegative than bromine which is more electronegative than iodine.
Halogen atoms are all capable of gaining an electron to form the negatively charged halide ion (general formula X-), but fluorine will do this more "completely" than iodine for example.

As the radius of the atom increases down group 17 from top to bottom, and the valence shell electrons are increasingly shielded, the positively charged nucleus exerts less of an attractive force on the electrons so it has less ability to attract electrons towards itself, hence, electronegativity decreases down the group from top to bottom.

And this means the chemical reactivity of the group 17 elements also decreases going down the group from top to bottom!
We expect fluorine to be more reactive than chlorine, and chlorine to more reactive than bromine, and bromine to be more reactive than iodine.

So let's consider the reaction between halogens and hydrogen to produce hydrogen halides.
These hydrogen halides are all covalent molecules and exist in the gaseous state at room temperature and pressure.

Group 17 Element Reaction with hydrogen Trend in Reaction Rate
fluorine F2(g) + H2(g) → 2HF(g) explosive reaction
chlorine Cl2(g) + H2(g) → 2HCl(g) vigorous reaction
bromine Br2(l) + H2(g) → 2HBr(g) rapid reaction
iodine I2(s) + H2(g) → 2HI(g) least vigorous reaction

There is a trend in the reactivity of the halogens, they become less reactive as you go down group 17 from top to bottom.

Halogens react with most non-metals to form covalent halides, and the reaction with fluorine is always the most vigorous!

Indeed, fluorine is so reactive that it reacts with most substances vigorously!
The ONLY reason we can store it in containers like steel is because it forms a fluoride coating on the metal surface which prevents any further reaction taking place with the fluorine.(4)

Halogens (group 17 elements) react with most metals to form an ionic metal halide, and the reactions are more vigorous with fluorine and least vigorous with iodine.

The halogens also react with water. Ofcourse the reaction with fluorine is vigorous, while the reaction with other halogens is much less so...

but fluorine reacts vigorously with water to produce hydrogen fluoride and oxygen gas:

2F2(g) + 2H2O(l) → 4HF(aq) + O2(g)

while the other halogens react with water only to a slight extent to produce hypohalous acids (HOX) (5):

Reaction with Water (6) Name of Hypohalous Acid product
Cl2(g) + H2O(l) ⇋ HOCl(aq) + H+(aq) + Cl-(aq) hypochlorous acid (HOCl)
Br2(g) + H2O(l) ⇋ HOBr(aq) + H+(aq) + Br-(aq) hypobromous acid (HOBr)
I2(g) + H2O(l) ⇋ HOI(aq) + H+(aq) + I-(aq) hypoiodous acid (HOI)

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Problem Solving using StoPGoPS method

Question: Chris the Chemist has been given a sealed specimen jar containing a sample of an element that is believed to be astatine.

In order to determine if this element is astatine Chris:

(a) describes its physical appearance at 25°C and 100 kPa

(b) determines its melting point

(c) reacts the element with hydrogen gas

Predict the results of each of Chris's tests assuming the sample is astatine.

STOP STOP! State the Question.
  What is the question asking you to do?
Describe the following properties of astatine:

(a) physical appearance (25°C, 100 kPa)

(b) melting point

(c) reaction with hydrogen gas

PAUSE PAUSE to Prepare a Game Plan
  (1) What information (data) have you been given in the question?

Element is thought to be astatine.

(2) What is the relationship between what you know and what you need to find out?

(i) Astatine is a Group 17 element (a halogen) and lies below iodine (I).

(ii) Going down group 17 from top to bottom, the following trends are observed:

(a) states: gas to liquid to solid

(b) colour transition: light colours to darker colours

(c) melting point increases

(d) reaction with hydrogen is increasingly less vigorous and produces a covalent gaseous hydrogen halide

GO GO with the Game Plan
 

(a) states: gas to liquid to solid

Iodine is a solid so astatine will be a solid.

(b) colour transition: light colours to darker colours

Iodine is a dark grey solid so astatine will be a darker grey solid, possibly black.

(c) melting point increases

Melting point of iodine is 114°C, melting point of astatine will be higher than this.
The difference in melting point between each successive group 17 element is about 110°C.
We could estimate the melting point of astatine to about 110 + melting point of iodine = 110 + 114 = 224°C

(d) reaction with hydrogen is increasingly less vigorous and produces a covalent gasoues hydrogen halide

Reaction between hydrogen and astatine will be less vigorous than the reaction between iodine and hydrogen.
The reaction might even be slow.
The reaction will be described by the equation below:
At2(s) + H2(g) → 2HAt(g)

PAUSE PAUSE to Ponder Plausibility
  Is your answer plausible?

Astatine will have a large atomic radius since it will have 6 occupied electron shells (energy levels).
The negatively-charged valence electrons will be well shielded from the positively charged nucleus.
Therefore, the ability of the nucleus to pull electrons towards itself will be relatively low and the chemical reactivity of astatine should be low.
Since astatine has 7 valence electrons it will want to gain 1 electron to complete it's octet of electrons, so the formula of its hydride will be HAt.
As the atomic radius increases down group 17, so does the melting point. Although each X2 molecule has no permanent dipole as the number of electrons in each atom increases then the possibility of fleeting deformities resulting in slightly unsymmeytrical charge clouds appears and the weak intermolecular forces acting between the halogen molecules increases as you go down group 17. Since it will require more energy to weaken these strengthened intermolecular forces, the melting point of halogens increases down the group, so astatine, being the last "naturally occurring" member of the group will have the highest melting point.
The melting point will higher than that of iodine (114°C) which is greater than room temperature (taken as 25°C) so astatine will be a solid at room temperature and pressure.

Since these arguments agree with the predictions we made above, we are reasonably confident that our answer is plausible.

STOP STOP! State the Solution
  Predicted properties of astatine:

(a) physical appearance (25°C, 100 kPa): dark-grey to black solid

(b) melting point: > 114°C (possibly about 224°C)

(c) reaction with hydrogen gas: At2(s) + H2(g) → 2AtH(g)

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Footnotes:

(1) Astatine does not occur naturally and its longest lived isotope has a half-life of only about 8 hours.

(2) "Halogen" comes from the Greeks meaning "salt formers"

(3) Astatine resembles iodine in chemical properties but is more metallic

(4) Fluorine can be stored in glass .... as long as no hydrogen fluoride, HF, is present because HF reacts with glass!
SiO2(s) + HF → SiF62- + 2H+ + 2H2O
HF is pretty nasty stuff. It causes very painful chemical burns that require months to heal.

(5) HOF, hypofluorous acid, has been observed but it is extremely unstable.

(6) The Ka values for these reactions are small, very few ions are in solution, most of the species present are the undissociated hypohalous acid molecules.